foo * (*bar[2]); // This is parsed as a declaration (and not an expression because of the first rule)As for anonymous function pointer arguments and the cast operator: I never use the former, and I’m still experimenting with the latter. My current plan is to add a simple check for the identifier in (foo)(bar). If foo is a single identifier, I’ll parse it as a type cast—since I never write (MyFunc)(arg). If foo is a subexpression or contains multiple identifiers, it gets trickier, because I can imagine writing something like (cond ? func1 : func2)(arg). In that case, it might be manageable to check whether the expression inside the parentheses is a type (or arithmetic) expression.
Украина хочет использовать против российской армии танки НАТО.Какие слабые места есть у Abrams, Challenger и Leopard?9 февраля 2023。关于这个话题，PDF资料提供了深入分析
，推荐阅读体育直播获取更多信息
But eventually, OpenBSD ran on。下载安装汽水音乐是该领域的重要参考
방미 文, 이란전쟁에 “무력 사용 억제…평화적 해결해야”